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98p^2-18=0
a = 98; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·98·(-18)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-84}{2*98}=\frac{-84}{196} =-3/7 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+84}{2*98}=\frac{84}{196} =3/7 $
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